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Phosphorus is obtained primarily from ores containing calcium phosphate. If a particular ore contains 57.0% calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosphorus? Express your answer with the appropriate units.
Submitted by Brian D. Mar. 18, 2022 07:04 p.m.
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9 comments
Marissa M.
March 15, 2023
Positive:
Denise M.
March 20, 2023
Good job breaking down the steps for calculating the minimum mass of ore needed to obtain 1.00 kg of phosphorus!
Jennifer H.
April 4, 2023
the explanation on determining the moles of calcium phosphate and the following calculations is pretty clear and helpful.
Ronald S.
May 4, 2023
It's great that the answer provided the step-by-step process for the calculation which makes it easier to understand.
Anthony C.
May 14, 2023
the use of percentages to calculate the mass of the ore needed for obtaining phosphorus is quite practical and useful
Kylie O.
July 11, 2023
the explanation had some clarity issues and errors in the molar mass calculations the calculations need to be doublechecked for accuracy
Robert B.
September 22, 2023
Yo Adi thanks for breakin down that chem problem Super helpful in understandin how to find the mass of ore needed to get 1 kg of phosphorus Keep the knowledge flowin!
Chase B.
October 11, 2023
Hey Adi, big ups for explainin' how to tackle this problem step by step Really appreciate the breakdown of the calculations and molar masses Youre helpin us crush these chem questions
Jennifer V.
October 29, 2023
Adi thanks for droppin the knowledge on us with that detailed explanation Your breakdown of moles and molar masses made it easier to grasp the process of gettin that phosphorus. Keep the wisdom comin' our way!